Le 17/12/2012 15:14, Tiago de Paula Peixoto a écrit :
Ok I'll do that, thanks!On 12/17/2012 11:59 AM, Guillaume Gay wrote:Is there a way to do the following differently: edge_x = g.new_edge_property() edge_x.a = np.array([x[e.source()] for e in g.edges()]) with x being a vector property map. I plain English, is there a (more efficient) way to copy the vertex property map of every edge source to an edge property map?Something like this is not yet available, you have to use a python loop for now. However I plan to add something like this at some point, since it occurs often enough. If you wish, you may open a ticket, and I'll address when time permits. Cheers, Tiago
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